7t^2-66=0

Solution for 7t^2-66=0 equation:

7t^2-66=0

a = 7; b = 0; c = -66;
Δ = b2-4ac
Δ = 02-4·7·(-66)
Δ = 1848
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{1848}=\sqrt{4*462}=\sqrt{4}*\sqrt{462}=2\sqrt{462}$
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-2\sqrt{462}}{2*7}=\frac{0-2\sqrt{462}}{14}
=-\frac{2\sqrt{462}}{14}
=-\frac{\sqrt{462}}{7}
$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+2\sqrt{462}}{2*7}=\frac{0+2\sqrt{462}}{14}
=\frac{2\sqrt{462}}{14}
=\frac{\sqrt{462}}{7}
$